v(6v^2+3v-7)=32v

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Solution for v(6v^2+3v-7)=32v equation: 



v(6v^2+3v-7)=32v

We move all terms to the left:

v(6v^2+3v-7)-(32v)=0

We add all the numbers together, and all the variables

-32v+v(6v^2+3v-7)=0

We multiply parentheses

6v^3+3v^2-32v-7v=0

We do not support evpression: v^3

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